Taboo Conspiracy - The Space Shuttle Joke Was on You - backs out of his Sun/Moon gravity claim
Dear Taboo Conspiracy,
Fact check = You FAIL
Your claim that ... "Weigh an object on an accurate scale when both the moon and sun are allegedly on the opposite side of the earth (below your feet). Then use the same accurate scale to measure the weight when both the moon and sun are above your head. If there's no change - then gravity is 100% BS."
WRONG - for a person standing on the Earth's surface that means...
a) when the Sun/Moon is directly overhead, your weight is You - Sun/Moon gravity
b) when the Sun/Moon is directly under your feet, your weight is You + Sun/Moon gravity
=> which leaves only the Earth's gravitational attraction on YOU
Conclusion = Your whole idea is preposterous and proves that you don't understand what gravity really is.
As such, how can you even comment about gravity?
Fact: The gravitational attraction of the (Sun/Moon) on anyone standing on the Earth's surface is very very very very minuscule, and therefore essentially has VERY LITTLE EFFECT ON YOU.
Your fallacy 1 - admitting that the Sun and Moon do exert a gravitational influence of the Earth ("weigh an object on an accurate scale") but yet denying and trying to prove that gravity does not exist. That is contradictory.
Fact: - the Earth's acceleration of gravity is 9.8 meters /sec/sec on the surface. That is why people don't just float off into the sky.
Fact - the Suns' acceleration of gravity is 274 meters /sec/sec on its own surface. BUT - since the Sun is so far away from the Earth, and all forces diminish in strength based on the inverse square law (double the distance away and the force is 1/4 of what it was), its effect on the Earth is nil...
g=G(M/r²)
g - local gravitational field
G - gravitational constant
M - mass of Sun
r - distance from Sun
G=6.67428×10^-11 N(m/kg)²
M=1.9891×10^30 kg
r=1 AU=149.60×10^9 m
g=0.0059 m/s²
So the Sun's acceleration of gravity on the Earth is 0.0059 meters/sec/sec, which is only .0006 percent that of the Earth gravity. No wonder you're not pulled and squashed every day by the Sun as it passes over head and sets below the horizon.
Fact - the Moon's acceleration of gravity as felt on the Earth is .000033 meters/sec/sec.
Fact - Even though the Sun is 391 times as far away from the Earth as the Moon, its force on the Earth is about 175 times as large. Yet its tidal effect is smaller than that of the Moon because tides are caused by the difference in gravity field across the Earth.
You FAIL for making claims that are unsubstantiated by real world evidence.
Fact check = You FAIL
After we pointed out to you that in order to have the Sun/Moon directly overhead, as your experiment requires - that could only happen for people living between the living between Tropic of Cancer (23° North) and the Tropic of Capricorn (23° South) on the Earth...
...you then stated it was acceptable to do the experiment even when the Sun/Moon was not directly overhead.
Fact check = You FAIL
Then when asked OK, then tell me at what date and time I could test your experiment from Columbus, Ohio, you just disappeared and no longer answered this question.
Conclusion - when you were finally put up against the wall, you had no explanation to back up your claim, so you just ran away and exited the scene.
So get a new life and stop spreading your flat Earth delusions!
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On September 5, 2017 you commented:
"The gravitational attraction of the (Sun/Moon) on anyone standing on the Earth's surface is very very very very minuscule ..." LOLOLOLOL! The gravity of moon supposedly causes the tides. The gravity of the sun supposedly holds the entire earth and all of the planets in their respective vortex orbits and can still yank comets leaving the solar system, cause those same comets to then double their speed to catch back up with the speeding away sun and still maintain steady tabular performances. Yet, you're claiming that the sun's supposed gravitational effect on us is "very very very minuscule"? Nonsense and I don't care how you try to spin it! You silly religious zealots believe in imaginary unproven forces that grab your feet and hold you to a ball twirling in a vortex through space chasing after a sun all based on a gravitational pull of a sun that is actually "very very very minuscule." Yeah, that moon gravity pulls the entire oceans on opposite sides of the earth at the same time but has no effect on a person or a weight on a digital scale. Wow! Brilliant stupidity! I actually plan on doing the centrifugal test on my next trip to Arizona. I'll test what happens on a digital scale as I travel from Flagstaff (6,910 feet elevation) to Lake Powell, Utah (3,652 feet). Under the globe model, the weight should weigh more in Flagstaff. I'm guessing the weight will weigh more at Lake Powell. Elevation changes are supposed to be very minor in comparison to latitude changes according to you globe faithful. We'll put it to the test.
Our answer: When considering the force of gravity, what is important is the mass (amount of material) of BOTH OBJECTS and the DISTANCE BETWEEN THEM.
For example:
the force of gravity between a 150-pound person and the Sun separated at distance 93-million miles is = 0.4 newton's
the force of gravity between the Earth and the Sun separated at distance 93-million miles is = 3,538,407,446,710,300,000,000 newton’s
which is basically 1 - heptillions times more
even though both the person and the Earth are the same distance away from the Sun
That is why the earth is locked in orbit by the Sun's gravity
The following calculator can be found at - https://www.ajdesigner.com/phpgravity/newtons_law_gravity_equation_force.php#ajscroll
Now concerning the proposed weight experiment that you want to do, from your two selected locations, you will not any definitive results on which to base any conclusions.
Those two locations are not far enough apart (by longitude) and the big difference in elevation will significantly affect your measurements.
Flagstaff AZ latitude & longitude 6,910 feet elevation
35.1983° N, 111.6513° W
Lake Powell UT latitude & longitude 3,652 feet elevation
37.0683° N, 111.2433° W
An easy experiment that you can do - that proves the Earth is a round rotating globe
http://flatearthlunacy.com/index.php/2-uncategorised/295-how-much-you-weigh-depends-upon-where-you-are-on-the-earth-because-it-s-a-rotating-sphere
Weight is different based upon Earth latitude. Based on the two locations that you selected, the differnce in weight due to the Earth's rotation will be about 0.45 grams.
Please choose two locations much farther apart (by longitude) and having the same general elevation above sea level.
September 7, 2017 update:
So after responding to his post and offering the above advice, Taboo Conspiracy deleted that post...
Published on - August 30, 2017
Discussion at - https://www.youtube.com/channel/UC7ipUKERU0tzYFxALJBli4A/discussion
Video at.. https://www.youtube.com/watch?v=eSaytVJ-5Go
kind regards, JonahTheScientist
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Update March 2019:
Chris Hadfield 18-minute uncut video from the ISS talking to grade 10 class
Zero Gravity on the ISS (International Space Station) proven once again.
https://www.youtube.com/watch?v=zUIa685ETgo
"Aboard the International Space Station, Expedition 35 Commander Chris Hadfield of the Canadian Space Agency fielded questions about life and research on the orbital laboratory during an in-flight educational event April 16 2013, with students gathered at Lockview High School in Fall River, Nova Scotia. Hadfield, who is the first Canadian to command the station, is scheduled to return to Earth in mid-May after a five-month mission."
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On a zero gravity plane flight, a single dive lasts only for about 30-seconds. So that video above is a genuine ISS demonstration.
The following is one company that will give you a zero gravity experience (we have no affiliation with them).
HOW LONG DOES THE FLIGHT LAST? HOW LONG WILL I FEEL WEIGHTLESS?
The flight portion of a ZERO-G Experience® lasts approximately 90 to 100 minutes. During the flight 15 parabolas are performed each providing about 30 seconds of reduced gravity or weightlessness. By the end of the flight you will log about 6-7 minutes of reduced gravity - that's about as much zero-gravity time as Alan Shepard experienced on America's first human spaceflight.
http://www.gozerog.com/index.cfm
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Your claim - "Weigh an object on an accurate scale when both the moon and sun are allegedly on the opposite side of the earth (below your feet). Then use the same accurate scale to measure the weight when both the moon and sun are above your head. If there's no change - then gravity is 100% BS."
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