# Flat Earth NOT - Jessie Johnson does not know the difference between momentum, gravity, free fall velocity, centrifugal force, and F = ma. So he continues to post misinformation

Dear Jessie Johnson,

It is very unfortunate that you never took 10th science. That would have saved you from making all of your current mistakes.

You seem not smart enough to realize that you are posting fabrications of science. In your mind, all your published delusions are correct.

We tried to help you set the record straight, with an introduction to the physics of momentum, gravity, free fall velocity. centrifugal acceleration, and force (F = MA), but you **DELETED OUR COMMENTS.**

Dear readers, here are some of Jessie's responses to us...

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In this post of his, he confuses the concepts momentum, gravity, free fall velocity, centrifugal force, and F = ma.

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He deleted our entire explanation as follows...

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**So why doesn’t Earth’s rotation fling us off in to space?**

Gravity attracts all objects toward the Earth’s center. The acceleration due to gravity at Earth’s surface is 9.8 meters per second, per second.

Centripetal force on Earth is the force of gravity acting on objects (us) orbiting Earth – we happen to orbit the Earth on its surface, at its exact speed of rotation, because gravity “glues” us to the surface as the Earth spins on its rotational axis.

Centrifugal force is the unbalanced reaction of inertia to centripetal force.

So centripetal force constantly “pulls” us toward the Earth as we orbit, while “centrifugal” force is the inertial tendency of mass (our bodies) to continue moving in a straight line (e.g. flung in to space).

The pound (lbs), in normal reference, is a unit of weight (force). The kilogram is a unit of mass.

Force = Mass * Acceleration (F=ma)

Now some calculations:

Earth’s circumference at the equator is about (40,075 km / 24901 miles). At the equator, Earth’s surface moves at about v=465 m/s (1,040 mph).

The Earth’s rate of rotation (w) is about 15 degrees per hour (.0042 deg/s), which of course equals one full rotation per day.

The Earth’s average radius (r=center to surface) is about 6,370 km.

Centripetal acceleration at the equator, a = v^2/r, is about .034 m/s/s.

**Since this minuscule force of .034 m/s/s - is only 0.34% of the force of gravity, it is nowhere strong enough to throw anyone off the Earth.**

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Centrifugal force caused by the Earth’s rotation is not any of those things mentioned.

It’s a different concept (circular motion) and set of calculations

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So f you say YES, that you understand what I presented above, then I will post the correct information on centrifugal force and gravity for you.

I hope you will read what I have written and take it seriously, because that is the reality.

Kind regards,

**Update December 16, 2017 - he never responded to our offer.**

Discussion at - https://www.youtube.com/channel/UC7ipUKERU0tzYFxALJBli4A/discussion

Video at - https://www.youtube.com/watch?v=gFJMEaY7JSY

Our home page all articles - http://flatearthlunacy.com/

kind regards, JonahTheScientist

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